Uh, OK. Let L0, L1, P0, P1 be the numbers of leronlimab and placebo deaths (0) and survivors (1). Then, calculate logit = LO = log[(L0 * P1/(L1 * P0)] as your test statistic, which is assumed to be normally distributed with sd = sqrt(1/L0 + 1/L1 + 1/P0 + 1/P1). Then, you can calculate z = LO/sd. The p-value would then be Pr(Z < z), where Z is a standard normal, which you can calculate as CDF[normaldistribution(0, 1), z], where z is the number you calculated. The p-value will be the "Result".

You can get slightly more accurate results for small numbers by adding a bias-correction factor of 0.5 to L0, L1, P0, and P1 wherever they appear.